Primality proof for n = 1013:
Take b = 2.
b^(n-1) mod n = 1.
23 is prime.
b^((n-1)/23)-1 mod n = 252, which is a unit, inverse 607.
2 is prime.
b^((n-1)/2)-1 mod n = 1011, which is a unit, inverse 506.
(2^2 * 23) divides n-1.
(2^2 * 23)^2 > n.
n is prime by Pocklington's theorem.