Primality proof for n = 10909:
<p>Take b = 2.
<p>b^(n-1) mod n = 1.
<p><a href=101.html>101 is prime.</a>
<br>b^((n-1)/101)-1 mod n = 228, which is a unit, inverse 10287.
<p><a href=3.html>3 is prime.</a>
<br>b^((n-1)/3)-1 mod n = 9266, which is a unit, inverse 4183.
<p>(3^3 * 101) divides n-1.
<p>(3^3 * 101)^2 > n.
<p>n is prime by Pocklington's theorem.