Primality proof for n = 13:
Take b = 2.
b^(n-1) mod n = 1.
3 is prime.
b^((n-1)/3)-1 mod n = 2, which is a unit, inverse 7.
2 is prime.
b^((n-1)/2)-1 mod n = 11, which is a unit, inverse 6.
(2^2 * 3) divides n-1.
(2^2 * 3)^2 > n.
n is prime by Pocklington's theorem.