Primality proof for n = 135193:

Take b = 2.

b^(n-1) mod n = 1.

131 is prime.
b^((n-1)/131)-1 mod n = 91799, which is a unit, inverse 92296.

43 is prime.
b^((n-1)/43)-1 mod n = 132648, which is a unit, inverse 8340.

(43 * 131) divides n-1.

(43 * 131)^2 > n.

n is prime by Pocklington's theorem.