Primality proof for n = 14593:
Take b = 5.
b^(n-1) mod n = 1.
19 is prime.
b^((n-1)/19)-1 mod n = 6036, which is a unit, inverse 1013.
3 is prime.
b^((n-1)/3)-1 mod n = 6682, which is a unit, inverse 2636.
2 is prime.
b^((n-1)/2)-1 mod n = 14591, which is a unit, inverse 7296.
(2^8 * 3 * 19) divides n-1.
(2^8 * 3 * 19)^2 > n.
n is prime by Pocklington's theorem.