Take b = 2.

b^(n-1) mod n = 1.

179 is prime.

b^((n-1)/179)-1 mod n = 1169853, which is a unit, inverse 1926011.

5 is prime.

b^((n-1)/5)-1 mod n = 1586638, which is a unit, inverse 1224329.

(5^4 * 179) divides n-1.

(5^4 * 179)^2 > n.

n is prime by Pocklington's theorem.