Primality proof for n = 6367:
Take b = 2.
b^(n-1) mod n = 1.
1061 is prime. b^((n-1)/1061)-1 mod n = 63, which is a unit, inverse 4750.
(1061) divides n-1.
(1061)^2 > n.
n is prime by Pocklington's theorem.