Primality proof for n = 6500537:
<p>Take b = 2.
<p>b^(n-1) mod n = 1.
<p><a href=103.html>103 is prime.</a>
<br>b^((n-1)/103)-1 mod n = 5010448, which is a unit, inverse 270428.
<p><a href=23.html>23 is prime.</a>
<br>b^((n-1)/23)-1 mod n = 4901119, which is a unit, inverse 803080.
<p><a href=7.html>7 is prime.</a>
<br>b^((n-1)/7)-1 mod n = 2957565, which is a unit, inverse 1102302.
<p>(7^3 * 23 * 103) divides n-1.
<p>(7^3 * 23 * 103)^2 > n.
<p>n is prime by Pocklington's theorem.