Primality proof for n = 761:
Take b = 2.
b^(n-1) mod n = 1.
19 is prime.
b^((n-1)/19)-1 mod n = 635, which is a unit, inverse 610.
5 is prime.
b^((n-1)/5)-1 mod n = 66, which is a unit, inverse 565.
(5 * 19) divides n-1.
(5 * 19)^2 > n.
n is prime by Pocklington's theorem.