Primality proof for n = 9613:
<p>Take b = 2.
<p>b^(n-1) mod n = 1.
<p><a href=89.html>89 is prime.</a>
<br>b^((n-1)/89)-1 mod n = 5873, which is a unit, inverse 7292.
<p><a href=3.html>3 is prime.</a>
<br>b^((n-1)/3)-1 mod n = 3085, which is a unit, inverse 2175.
<p>(3^3 * 89) divides n-1.
<p>(3^3 * 89)^2 > n.
<p>n is prime by Pocklington's theorem.